Question

Alguém sabe essa x2-7×+10=0

Answer 1

x²-7x+10=0

∆=b²-4ac
∆=(-7)²-4*10*1
∆=49-40
∆=9

-b±√∆/2a

-(-7)±√9/2*1

x'(7+3)/2=10/2 =5
x"=(7-3)/2=4/2 =2

S{5,2}