Question

20 pontos preciso muito dessas respostas

Answer 1

$x=-3 ~;~y=-6~;~z=-5\\\\ \dfrac{x^2+y^2}{3z} \to~~~ \dfrac{(-3)^2+(-6)^2}{3.(-5)} \to~~~ \dfrac{9+36}{-15} \to~~~ -\dfrac{45}{15} \to~~~ \large\boxed{-3}$



Resposta: Letra C) - 3