Question

dtermine o conjunto verdade das equações exponenciais​

Answer 1

Explicação passo-a-passo:

Lembrando que:

$\boxed{a^{x}.a^{y}=a^{x+y} } \\\\\boxed{\dfrac{a^{x}}{a^{y}} =a^{x-y}}$

Resolvendo a equação exponencial:

$2^{x+2} +2^{x-1}=18\\\\2^{x}. 2^{2}+\dfrac{2^{x}}{2^{1}} =18\\\\4.2^{x}+\dfrac{2^{x}}{2}=18\\\\\dfrac{8.2^{x}}{2}+\dfrac{2^{x}}{2}=18\\\\\dfrac{9.2^{x}}{2}=18\\\\9.2^{x}=18.2\\\\9.2^{x} =36\\\\2^{x}=\dfrac{36}{9}\\\\2^{x}=4\\\\2^{x}=2^{2}\\\\\text Igualando\ os\ expoentes:\\\\\boxed{x=2}\\\\\boxed{\boxed{V=\{2\}}}$