Question

aplique as propriedades das potências em cada caso

Answer 1

Resposta:

$a)34^2*34^5=34^7\\\\b)4^5*4^8*4^3=4^{16}\\\\c)(\frac{5}{7})^8:(\frac{5}{7})^5=(\frac{5}{7})^3 \\\\d)1,25^6:(1,25^3*1,25^2)=1,25^6:1,25^5=1,25$

Answer 2

Resposta:

a) 34^2 . 34^5 = 34^2+5 = 34^7                      

b) 4^5. 4^8. 4^3 = 4^5+8+3 = 4^16                  

c)(5/7)^8 : (5/7)^5 = (5/7)^8-5 = (5/7)^3  

d)1,25^6 : (1,25^3 . 1,25^2) = 1,25^6 : 1,25^3+2 = 1,25^6 : 1,25^5 = 1,25^6-5 = 1,25^1

a) 34^7                      

b) 4^16        

c) (5/7)^3  

d)  1,25^1

Explicação passo-a-passo:

Espero ter ajudado:)