Question

torne as seguintes frações em irredutíveis:
9/6
15/24
16/6
28/49
35/45
36/27
105/63
68/64

Answer 1

$\frac{9}{6} : \frac{3}{3} = \frac{3}{2}$

$\frac{16}{6} : \frac{2}{2} = \frac{8}{3}$

$\frac{28}{49} : \frac{7}{7} = \frac{4}{7}$

$\frac{35}{45}$ : $\frac{5}{5} = \frac{7}{9}$

$\frac{36}{27}$ : $\frac{9}{9}$ =$\frac{4}{3}$

$\frac{105}{63}$ : $\frac{7}{7} = [tex] \frac{15}{9}$