Question

Quais os zeros da função f(x)=x²+x-6

a) -1 e 6
b) 1 e -6
c) -1 e -6
d) 1 e 6
e) 0 e 1

Answer 1

DELTA = 1² + 24
DELTA = 25
X=-1+- RAIZ DE 25/2
X=-1+5/2=4/2=2

X´-1+5/2 = 4/2 = 2
X´´= -1-5/2 = -6/2 = -3

=2 E -3 espero ter ajudado

Answer 2

Explicação passo-a-passo:

$\sf x^2+x-6=0$

$\sf \Delta=1^2-4\cdot1\cdot(-6)$

$\sf \Delta=1+24$

$\sf \Delta=25$

$\sf x=\dfrac{-1\pm\sqrt{25}}{2\cdot1}=\dfrac{-1\pm5}{2}$

$\sf x'=\dfrac{-1+5}{2}~\Rightarrow~x'=\dfrac{4}{2}~\Rightarrow~\red{x'=2}$

$\sf x"=\dfrac{-1-5}{2}~\Rightarrow~x"=\dfrac{-6}{2}~\Rightarrow~\red{x"=-3}$

Os zeros dessa função são $\sf 2~e~-3$