• Matéria: Matemática
  • Autor: Dadivanocampo99
  • Perguntado 5 anos atrás

Resolva a expressão:

4.sen² x - 1 = 0

( ) 225°
( ) 60°
( ) 120°
( ) 150°

Respostas

respondido por: elizeugatao
0

\displaystyle 4\text{sen}^2(\text x)-1 = 0 \\\\ 4\text{sen}^2(\text x) = 1 \\\\ \text{sen}^2(\text x) = \frac{1}{4} \\\\ \text{sen(x)}= \pm \sqrt{\frac{1}{4}} \\\\\\ \text{sen(x)} = \frac{1}{2} \ \ \text{ou} \ \ \text{sen(x)} = \frac{-1}{2}

Vamos analisar :

\displaystyle \text{sen(x)} = \frac{1}{2} \\\\\text x  = \{30^\circ+ 2\text k.\pi \ ,\  150^\circ+2\text k.\pi \ \} \ \boxed{\text{com k }  \in \mathbb{Z}}

Portanto :

\huge\boxed{\text x = 150^\circ}\checkmark

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