Question

me ajuudeem pfvvv!!​

Answer 1

Explicação passo-a-passo:

instala esse aplicativo, ele tem as respostas

Answer 2

Resposta:

$a)( \sqrt{21} )^{2} = ({21}^{ \frac{1}{2} })^{2} = {21}^{ \frac{1}{2} \times ^{2} } = {21}^{ \frac{2}{2} } = 21$

$b)( \sqrt[3]{4})^{2} =( {4}^{ \frac{1}{3}} )^{2} = {4}^{ \frac{1}{3} \times ^{2} } = {4}^{ \frac{2}{3} } = \sqrt[3]{ {4}^{2} }$

$c)(8 \sqrt{3} )^{2} = {8}^{2} \times ({3}^{ \frac{1}{2} } )^{2} = 64 \times {3}^{ \frac{2}{2} } = 64 \times 3 = 192$

$d)( \sqrt[4]{2} )^{9} = ( {2}^{ \frac{1}{4} })^{9} = {2}^{ \frac{9}{4} } = \sqrt[4]{ {2}^{9} }$

$e)( \frac{1}{2} \sqrt{10})^{2} = (\frac{1}{2})^{2} \times ( {10}^{ \frac{1}{2} })^{2} = \frac{1}{4} \times {10}^{ \frac{2}{2} } = \frac{1}{4} \times 10 = \frac{1 0}{4} = \frac{10 \div 2}{4 \div 2} = \frac{5}{2}$

$f)( \sqrt[6]{8})^{2} = ( {8}^{ \frac{1}{6} } )^{2} = {8}^{ \frac{2}{6} } = {8}^{ \frac{2 \div 2}{6 \div 2} } = {8}^{ \frac{1}{ 3} } = \sqrt[3]{8} = 2$

Espero ter te ajudado.