Question

se x=√2, y=√98-√32-√8 entao
a)y=3x
b)y=5x
c)y=x
d)y=7x

Answer 1

$x= \sqrt{2}$

$y = \sqrt{98}- \sqrt{32}- \sqrt{8} = \sqrt{2*7^2} - \sqrt{2^2*2^2*2} - \sqrt{2^2*2} \\ y = 7 \sqrt{2}-4 \sqrt{2}-2 \sqrt{2} \\ y = \sqrt{2}$

$\boxed{y = x}$

Letra C.

Espero ter ajudado. :))