Question

aplicando a formula de baskara 3×2-7×+4=0

Answer 1

3x²-7x+4=0
a=3
b=-7
c=4
Δ=b²-4.a.c
Δ=(-7)²-4.3.4
Δ=49-48
Δ=1
x=-b+-√Δ /2.a
x=-(-7)+-√1/2.3
x=7+-1/6
x'=7+1/6=1.33
x"=7-1/6=1

Answer 2

3x² - 7x + 4 = 0
a = 3; b = - 7; c = 4

Δ = b² - 4ac
Δ = (-7)² - 4.3.4
Δ = 49 - 12.4
Δ = 49 - 48
Δ = 1

x = - b +/- √Δ = - ( - 7) +/- √1
           2a                2.3

x' = 7 + 1 = 8  (:2)  =  4
         6       6  (:2)      3

x" = 7 - 1 = 6/6 = 1
         6

R.: x = 4/3 e x = 1