Question

Dados x=log0,25 (1/16) e y=Log√3 81, calcule x+y

Answer 1

x = log 0,25 (1/16) = log 25/100 (2^-4) = log (1/4) (4^-2)

4^-x = 4^-2
-x = -2
x = 2

y =  log √3 (81) = log 3^(1/2) 3^4 =

3^-2y = 3^4
-2y = 4
y = 4/-2
y = -2

x+y = 2 - 2 = 0