Question

log 3 (4 + x ) = log 3 (-3x – 4)

Answer 1

 f(x) = log3[(3x + 4)/(2x - 1)]

log3[(3x + 4)/(2x - 1)] > 1

[(3x + 4)/(2x - 1)] > 3

3x + 4 > 3.(2x - 1)

3x + 4 > 6x - 3

3x - 6x > -3 - 4

-3x > -7

3x < 7

x < 7/3