Question

equação do 2°grau quem puder me ajuda por favor
2x²+5x=0
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Answer 1

2x²+5x=0

a= 2 b= 5 c=0

Δ = b²-4ac

Δ = 5²-4.2.0

Δ = 25 - 0

Δ = 25

$x' = \frac{-5+\sqrt{25}}{2*2}\\\\ =\frac{-5+5}{4} =0 \\ \\x"= \frac{-5-\sqrt{25}}{2*2}\\ \\\frac{-5-5}{4} = \frac{-10}{4} = \frac{-5}{2}$