Question

o vertice da parabola y=2x²-4x +5

Answer 1

2x²-4x+5=0
∆=b²-4ac
∆=(-4)²-4.2.5
∆=16-40
∆=-24
xv=-b/2a
xv=-(-4)/2.2
xv=4/4
xv=1
yv=-∆/4a
yv=-(-24)/4.2
yv=24/8
yv=3
(1, 3)