Question

Dado o polinomio p(x)=2x³-x²+3x-5, determine P(0)+2P(1).

Answer 1

p(x)=2x³-x²+3x-5, determine P(0)+2P(1).

p(0)= 2(0)³- (0)²+3(0)-5==> 2.(0)-0-5==>0+0-5==>p(0) = - 5

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p(1)=2(1)³- (1)²+3(1)-5 ==>2 -1+3-5==>p(1) = - 1

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p(0) + 2P(1) = - 5 - 2 ==> -7

Answer 2

P(0)+2P(1)=
2.0³-0²+3.0-5+2.(2.1³-1²+3.1-5)=
-5+2.(2-1+3-5)=
-5+2.(-1)=
-5-2=
-7

ou
faz separado
P(0)=2.0³-0²+3.0-5=-5
2P(1)=2.(2.1³-1²+3.1-5)=2.(-1)=-2
soma no final
-5-2=-7