Question

PRECISO DE AJUDA,OBRIGADO

Answer 1

Resposta:

Explicação passo-a-passo:

I.

$3(x-a)=2(b+x)+6c\\3x-3a=2b+2x+6c\\\\3x-3\left[\begin{array}{ccc}2&1\\3&-1\\\end{array}\right] =2\left[\begin{array}{ccc}-1&2\\1&0\\\end{array}\right] +2x+6\left[\begin{array}{ccc}4&-1\\2&1\\\end{array}\right] \\\\3x-2x-\left[\begin{array}{ccc}6&3\\9&-3\\\end{array}\right] =\left[\begin{array}{ccc}-2&4\\2&0\\\end{array}\right] +\left[\begin{array}{ccc}24&-6\\12&6\\\end{array}\right] \\\\x=\left[\begin{array}{ccc}22&-2\\14&6\\\end{array}\right] +\left[\begin{array}{ccc}6&3\\9&-3\\\end{array}\right]$

$x=\left[\begin{array}{ccc}28&1\\23&3\\\end{array}\right]$

II.

$\left \{ {{x+y=a+3b} \atop {x-y=3a-2b}} \right. \\+-----\\2x=4a+b\\\\2x=4\left[\begin{array}{ccc}1\\0\\2\end{array}\right] +\left[\begin{array}{ccc}4\\2\\0\end{array}\right] \\\\\\2x=\left[\begin{array}{ccc}4\\0\\8\end{array}\right] +\left[\begin{array}{ccc}4\\2\\0\end{array}\right]\\\\\\2x=\left[\begin{array}{ccc}8\\2\\8\end{array}\right]\\\\\\x=\left[\begin{array}{ccc}4\\1\\4\end{array}\right]$

$x+y=a+3b\\y=a+3b-x\\\\y=\left[\begin{array}{ccc}1\\0\\2\end{array}\right]+3\left[\begin{array}{ccc}4\\2\\0\end{array}\right]-\left[\begin{array}{ccc}4\\1\\4\end{array}\right]\\\\\\y=\left[\begin{array}{ccc}1\\0\\2\end{array}\right]+\left[\begin{array}{ccc}12\\6\\0\end{array}\right]-\left[\begin{array}{ccc}4\\1\\4\end{array}\right]\\\\\\y=\left[\begin{array}{ccc}9\\5\\-2\end{array}\right]$

Espero ter ajudado!

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