Question

resolva a equação 2ײ-×+1=0

Answer 1

$2 x^{2} -x+1=0\\\\ a=2~;~b=-1~;~c=1\\\\\\ \Delta=b^2-4ac\to \Delta=(-1)^2-4.2.1\to \Delta=1-8\to \boxed{\Delta=-7}\\\\\\ { \it N\~ao ~~existe~~raiz~~dentro~~dos~~reais,~~pois~~ \Delta\ \textless \ 0.}$

Answer 2

2ײ-×+1=0
Δ = (-1)² - 4.2.1 = 1 - 8 ==> - 7  

Δ < 0 não existe raiz.