Question

a raiz quadrada de 8 / 2 vezes raiz quadrada de 2 /4


AJUDEM POR FAVOR​

Answer 1

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$\large\boxed{\begin{array}{l}\sf\dfrac{8}{2\sqrt{\frac{2}{4}}}=8\div\bigg(2\sqrt{\dfrac{2}{4}}\bigg)\\\sf=8\div\bigg(2\cdot\dfrac{\sqrt{2}}{\sqrt{4}}\bigg)\\\sf=8\div\bigg(\diagup\!\!\!2\cdot\dfrac{\sqrt{2}}{\diagup\!\!\!2}\bigg)\\\sf=8\div\sqrt{2}=\dfrac{8}{\sqrt{2}}\\\sf=\dfrac{8}{\sqrt{2}}\cdot\dfrac{\sqrt{2}}{\sqrt{2}}\\\sf=\dfrac{8\sqrt{2}}{\sqrt{2^{\diagup\!\!\!\!2}}}=\dfrac{8\sqrt{2}}{2}=4\sqrt{2}\end{array}}$

Answer 2

$\sf \displaystyle \sqrt{\frac{8}{2}}\cdot \sqrt{\frac{2}{4}}\\\\\\\sf {Aplique\:as\:propriedades\:dos\:radicais}:\quad \sqrt{a}\sqrt{b}=\sqrt{a\cdot b}\\\\\\\sf \sqrt{\frac{8}{2}}\sqrt{\frac{2}{4}}=\sqrt{\frac{8}{2}\cdot \frac{2}{4}}\\\\\\\sf =\sqrt{\frac{8}{2}\cdot \frac{2}{4}}\\\\\\\to \large\boxed{\sf \boxed{\sf =\sqrt{2}}}$