Question

Me ajudem pfvr, pra hj!
Com cálculo​

Answer 1

$\sqrt{648} : \sqrt{4} = \sqrt{648:4} = \sqrt{162} \\\\\sqrt{72} * \sqrt{12} = \sqrt{72*12} = \sqrt{912} \\\\\sqrt[3]{1875} * \sqrt[3]{3} = \sqrt[3]{1875*3} = \sqrt[3]{625}\\\\\sqrt[4]{144} : \sqrt[4]{9} = \sqrt[4]{144:9} = \sqrt[4]{16}\\\\\sqrt{12} * \sqrt{14} : \sqrt{3} = \sqrt{12*14} : \sqrt{3} =\sqrt{168} : \sqrt{3} = \sqrt{168:3} = \sqrt{56}\\\\\sqrt[3]{320} : \sqrt[3]{5} * \sqrt[3]{20} = \sqrt[3]{320:5} * \sqrt[3]{20} = \sqrt[3]{64} * \sqrt[3]{20} = \sqrt[3]{1280}$

Qualquer coisa que tu ver de errado me avisa. Eu revisei mas as vezes os erros passam batidos.