Question

pe) Doda a função y=x2-5x + 6, determine o zero da função.​

Answer 1

$y=ax^2+bx+c\ \to\ y=x^2-5x+6\ \to\ \boxed{a=1,\ b=-5,\ c=6}$

$y=0\ \therefore\ x^2-5x+6=0\ \to\ \boxed{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

$x=\dfrac{-(-5)\pm\sqrt{(-5)^2-4(1)(6)}}{2(1)}=\dfrac{5\pm\sqrt{25-24}}{2}=\dfrac{5\pm1}{2}$

$x_1=\dfrac{5-1}{2}=\dfrac{4}{2}\ \therefore\ \boxed{x_1=2}$

$x_2=\dfrac{5+1}{2}=\dfrac{6}{2}\ \therefore\ \boxed{x_2=3}$

Answer 2

Resposta:

Explicação passo-a-passo:

y = x² - 5x  + 6

x² - 5x  + 6 = 0

Δ = b² -4 .a .c

Δ = (-5)² - 4 (1) (6)

Δ = 25 - 24

Δ = 1

x = - b ±√Δ

          2a

$X_{1}$ = - (-5)+√1 =  5  +  1   =   6   =  3

            2(1)             2            2

       

$X_{2}$ = - (-5) - √1  = 5  -  1  = 4  =  2

            2(1)              2        2