Question

(-3)²×[-9+(-3)³]÷(3)²​

Answer 1

→ Cálculo :

$(-3)^{2} \times[-9+(-3)^{3} ]\div(3)^{2}$

$9\times[-9+(-27)]\div9=$

$9\times[-9-27]\div9=$

$9\times[-36]\div9=$

$1\times36=$

$\boxed{\red{ \ \ 36 \ \ }}$