Question

dê o valor de tg 210°,sen315°,COS135°,COSSEC150°

Answer 1

a) tg210 = tg30 = (raiz de 3)/3

b) sen316 = - sen45 = - (raiz de 2)/2

c) cos135 = - cos45 = - (raiz de 2)/2

d) cossec150 = 1 /sen150
1/sen150 = 1/cos60 = 1/(1/2) = 2