Question

alguém por favor me ajuda por favor me ajuda preciso pra agora​

Answer 1

$(a_1,a_2,a_3,a_4,\dots)=(4,6,8,10,\dots)\\\\ \boxed{a_n=a_k+(n-k)r}$

$a_2=a_1+r\ \therefore\ r=a_2-a_1=6-4\ \therefore\ \boxed{r=2}$

$a_{51}=a_1+50r=4+50(2)\ \therefore\ \boxed{a_{51}=104}$

Answer 2

Resposta:

(a

1

,a

2

,a

3

,a

4

,…)=(4,6,8,10,…)

a

n

=a

k

+(n−k)r

a_2=a_1+r\ \therefore\ r=a_2-a_1=6-4\ \therefore\ \boxed{r=2}a

2

=a

1

+r ∴ r=a

2

−a

1

=6−4 ∴

r=2

a_{51}=a_1+50r=4+50(2)\ \therefore\ \boxed{a_{51}=104}a

51

=a

1

+50r=4+50(2) ∴

a

51

=104