• Matéria: Matemática
  • Autor: hgleal
  • Perguntado 4 anos atrás

SE 2,63333333= a/b, então quanto será a-b?

Respostas

respondido por: niltonjunior20oss764
0

\bigg(\dfrac{a}{b}\bigg)=2.6\bar{3}\ \therefore\ 10\bigg(\dfrac{a}{b}\bigg)=26.\bar{3}\ \therefore\ 100\bigg(\dfrac{a}{b}\bigg)=263.\bar{3}a-b=79-30\ \therefore\ \boxed{a-b=49}

100\bigg(\dfrac{a}{b}\bigg)-10\bigg(\dfrac{a}{b}\bigg)=263.\bar{3}-26.\bar{3}\ \therefore\ 90\bigg(\dfrac{a}{b}\bigg)=237\ \therefore

\bigg(\dfrac{a}{b}\bigg)=\dfrac{237}{90}\ \therefore\ \boxed{\bigg(\dfrac{a}{b}\bigg)=\dfrac{79}{30}}\ \to\ \boxed{a=79}\ \text{e}\ \boxed{b=30}

a-b=79-30\ \therefore\ \boxed{a-b=49}

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