Question

ajuda ai porfavor, precisa urgente​

Answer 1

$x=1.\bar{3}\ \therefore\ 10x=13.\bar{3}\\\\ 10x-x=13.\bar{3}-1.\bar{3}\ \therefore\\\\ 9x=12\ \therefore\ \boxed{x=\dfrac{4}{3}}$

$y=0.1\bar{6}\ \therefore\ 10y=1.\bar{6}\ \therefore\ 100y=16.\bar{6}\\\\ 100y-10y=16.\bar{6}-1.\bar{6}\ \therefore\\\\ 90y=15\ \therefore\ \boxed{y=\dfrac{1}{6}}$

$x+y=1.\bar{3}+0.1\bar{6}=\dfrac{4}{3}+\dfrac{1}{6}=$

$\dfrac{8}{6}+\dfrac{1}{6}=\dfrac{9}{6}=\boxed{\dfrac{3}{2}}$

Letra E.