• Matéria: Física
  • Autor: bs8604774
  • Perguntado 4 anos atrás

física alguém me ajuda pfvr???​

Anexos:

Respostas

respondido por: niltonjunior20oss764
0

1)

Q=100\ C,\  t=5\ s\\\\ i=\dfrac{Q}{t}=\dfrac{100}{5}\ \therefore\ \boxed{i=20\ A}

2)

i=150\ A,\ t=20\ s,\ e=1.6\times10^{-19}\ C\\\\ Q=it=150(20)\ \therefore\ \boxed{Q=3\times10^3\ C}\\\\ Q=ne\ \therefore\ 3\times10^3=n(1.6\times10^{-19})\ \therefore\\\\ \boxed{n=1.875\times10^{22}\ \mathrm{el\acute{e}trons}}

3)

A carga será igual a área do gráfico i\times t:

t=20\ s,\ i=40\ mA=4\times10^{-2}\ A\\\\ Q=it=4\times10^{-2}(20)\ \therefore\ \boxed{Q=0.8\ C}

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