Question

Considere a equação (n-3)!=6(n-4)!

Answer 1

$\sf{(n - 3)! = 6(n - 4)!} \\ \sf{(n - 3)! - 6 \times (n - 4)! = \cancel{6 \times (n - 4)! - 6 \times (n - 4)!} }\\ \sf{(n - 3)! - 6 \times (n - 4)! = 0} \\ \sf{(n - 3) \times (n - 4)! - 6 \times (n - 4)! = 0} \\ \sf{(n - 4)! \times (n - 3 - 6) = 0} \\ \sf{(n - 4)! \times (n - 9) = 0} \\ \sf{(n - 4)! = 0} \\ \sf{n - 9 = 0} \\ \sf{n \in \emptyset} \\ \sf{n = 9} \\ \boxed{n = 9}$

Att: Armando

Answer 2

Explicação passo-a-passo:

(n - 3)! = 6( n - 4)!