• Matéria: Matemática
  • Autor: Rafa6262
  • Perguntado 4 anos atrás

Ache o valor da expressao:
15π
2

sen 8TT+cos 11π -sen

Anexos:

Respostas

respondido por: SwiftTaylor
4
  • Vamos a Expressão

\\\\\\\sf \displaystyle sen8\pi +cos11\pi -sen\frac{15\pi }{2}\\\\\\\sf sin \left(\frac{15\pi }{2}\right)=cos \left(\frac{\pi }{2}-\frac{15\pi }{2}\right)\\\\\\\sf =sin \left(8\pi \right)+\cos \left(11\pi \right)-cos \left(\frac{\pi }{2}-\frac{15\pi }{2}\right)\\\\\\\sf =sin \left(8\pi \right)+cos \left(11\pi \right)-cos \left(-7\pi \right)\\\\\\\sf =sin \left(8\pi \right)+cos \left(11\pi \right)-cos \left(7\pi \right)

\sf \sf =sin \left(0\right)+cos \left(11\pi \right)-cos \left(7\pi \right)\\\\\\\sf =sin \left(0\right)+cos \left(\pi \right)-cos \left(7\pi \right)\\\\\\\sf =sin \left(0\right)+cos \left(\pi \right)-cos \left(\pi \right)\\\\\\=sin \left(0\right)

  • Use a identidade trivial de sen(0) =0

\boxed{\sf S=\{ 0\}}

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