Question

a solução real da equação log3[2x/(x+1)]=-1

Answer 1

$\log_3\left[\dfrac{2x}{x+1}\right]=-1\Longleftrightarrow3^{-1}=\dfrac{2x}{x+1}\\\\\\\dfrac{1}{3}=\dfrac{2x}{x+1}\\\\\\6x=x+1\\\\5x=1\\\\x=\dfrac{1}{5}\\\\\\\boxed{S=\left\{\dfrac{1}{5}\right\}}$