Question

Sendo log2 = 0,3010 e Log7 = 0,8451 calcule log 140

Answer 1

$\boxed{\log_k{(a\times b)}=\log_k{a}+\log_k{b}}$

$\log{140}=\log{(2\times7\times10)}=\log{2}+\log{7}+\log{10}$

Sendo $\log{2}\approx0.301$, $\log{7}\approx0.8451$ e $\log{10}=1$, teremos:

$\log{140}\approx0.301+0.8451+1\ \to\ \boxed{\log{140}\approx2.1461}$