Question

Resolva as equações.
a) 4(x - 5) = 3x

b) 2 + 3(y – 5) = 4(y - 1)
C) 10z + 3(2-z)= 5(x+2)-4

D)3(x-7)=x-6
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E) 2(4x+40)-(x-4)=7(x-2)
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Answer 1

Explicação passo-a-passo:

a)

$4(x - 5) = 3x \\ 4x - 20 = 3x \\ 4x - 3x = + 20 \\ x = 20$

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b)

$2 + 3(y - 5) = 4(y - 1) \\ 2 + 3y - 15 = 4y - 4 \\ 3y - 4y = - 4 - 2 + 15 \\ - y =9 \\ y = - 9$

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c)

$10z + 3(2 - z) = 5(x + 2) - 4 \\ 10z + 6 - 3z = 5x + 10 - 4 \\ 10z - 3z = 5x \\ 7z = 5x \\ z = \frac{5}{7} x$

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d)

$\frac{3(x - 7)} {2} = x - 6 \\ \\ \frac{3x - 21}{2} = x - 6 \\ \\ 3x - 21 = 2x - 12 \\ 3x - 2x = - 12 + 21 \\ x = 9$

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e)

$\frac{2(4x + 40) - (x - 4)}{2} = 7(x - 2) \\ \frac{8x + 80 - x + 4}{2} = 7x - 14 \\ \frac{7x + 84}{2} = 7x - 14 \\ 7x + 84 = 14x - 28 \\ 7x - 14x = - 28 - 84 \\ - 7x = - 112 \\ x = \frac{ - 112}{ - 7} \\ x = 16$

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Espero ter ajudado!