Question

SOCORRO E PRA ENTREGA HOJEEE 4)calcule: a) (-2x^4y^3) : (-6xy) b) (2/3 a^5b^7) : ( - 4/9 a^3b^4) C) (1,6 a^3b) : (0,8 ab)

Answer 1

Resposta:

a) x³y²/3

b) -3/2a²b³

c) 1,6a²/0,8

Explicação passo-a-passo:

a) $\frac{-2x^4y^3}{-6xy}$

$=\frac{2x^4y^3}{6xy}\\=\frac{x^4y^3}{3xy}\\=\frac{x^3y^3}{3y}\\=\frac{x^3y^2}{3}$

b) $\frac{\frac{2}{3a^5b^7}}{\frac{-4}{9a^3b^4}}$

$=\frac{\frac{2}{3a^5b^7}}{-\frac{4}{9a^3b^4}}\\=-\frac{\frac{2}{3a^5b^7}}{\frac{4}{9a^3b^4}}\\=-\frac{2\cdot \:9a^3b^4}{3a^5b^7\cdot \:4}\\=-\frac{18a^3b^4}{12a^5b^7}\\=\frac{3a^3b^4}{2a^5b^7}\\=\frac{3b^4}{2b^7a^{5-3}}\\=\frac{3b^4}{2a^2b^7}\\=\frac{3}{2a^2b^{7-4}}\\=-\frac{3}{2a^2b^3}$

c) $\frac{1,6a^3b}{0,8ab}$

$=\frac{1,6a^3}{0,8a}\\=\frac{1,6a^2}{0,8}$