Question

em cada item calcule o comprimento aproximado do arco de circunferência em vermelho determinado pelo ângulo central indicado. nas circuferencias o ponto O e o Centro, e a medida do raio esta indicada ​

Answer 1

Resposta:

Explicação passo-a-passo:

a)

$\stackrel{\frown}{AB} = \dfrac{\pi ~. ~r~. ~\Phi}{180^o} \\ \\ \\\stackrel{\frown}{AB} = \dfrac{3,14 ~. ~3~. ~75}{180^o} \\ \\ \\\stackrel{\frown}{AB} = \dfrac{9,42~. ~75}{180^o} \\ \\ \\\stackrel{\frown}{AB} = \dfrac{706,5}{180^o} \\ \\ \\\stackrel{\frown}{AB} = 3,925 ~ m$

===

b)

$\stackrel{\frown}{CD} = \dfrac{\pi ~. ~r~. ~\Phi}{180^o} \\ \\ \\\stackrel{\frown}{CD} = \dfrac{3,14 ~. ~45~. ~180}{180^o} \\ \\ \\\stackrel{\frown}{CD} = \dfrac{141,3~. ~180}{180^o} \\ \\ \\\stackrel{\frown}{CD} = \dfrac{25434}{180^o} \\ \\ \\\stackrel{\frown}{CD} = 141,3 ~dm$

===

c)

$\stackrel{\frown}{EF} = \dfrac{\pi ~. ~r~. ~\Phi}{180^o} \\ \\ \\\stackrel{\frown}{EF} = \dfrac{3,14 ~. ~2,8~. ~44}{180^o} \\ \\ \\\stackrel{\frown}{EF} = \dfrac{8,792~. ~180}{180^o} \\ \\ \\\stackrel{\frown}{EF} = \dfrac{1582,56}{180^o} \\ \\ \\\stackrel{\frown}{EF} = 8,792 ~m$

===

d)

$\stackrel{\frown}{GH} = \dfrac{\pi ~. ~r~. ~\Phi}{180^o} \\ \\ \\\stackrel{\frown}{GH} = \dfrac{3,14 ~. ~3,7~. ~270}{180^o} \\ \\ \\\stackrel{\frown}{GH} = \dfrac{11,618~. ~180}{180^o} \\ \\ \\\stackrel{\frown}{GH} = \dfrac{2091,24}{180^o} \\ \\ \\\stackrel{\frown}{GH} = 11,618 ~m$

Answer 2

Resposta:

Explicação passo-a-passo: