Question

quais são as raízes da equação (x-3) (x-2)

Answer 1

$(x-3)(x-2)$
$x^2-2x-3x+6$
$x^2+(-2x-3x)+6$
$x^2-5x+6$

Bhaskara

$a=1$
$b=-5$
$c=6$

$\Delta=(b^2-4*a*c)$
$\Delta=(-5^2-4*1*6)$
$\Delta=(25-24)$
$\Delta=(1)$

$x=\frac{-b\pm \sqrt{\Delta}}{2*a}$
$x=\frac{-(-5) \pm \sqrt{1}}{2*1}$
$x=\frac{5 \pm 1}{2}$

$x'=\frac{5+1}{2}$
$x'=\frac{6}{2}$
$x'=3$

$x"=\frac{5-1}{2}$
$x"=\frac{4}{2}$
$x"=2$

As raízes são 2 e 3.