Question

Me ajudem por favor
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Answer 1

Explicação passo-a-passo:

01.

a) $5^2=25$

b) $3^4=81$

c) $83^1=83$

d) $2^3=8$

e) $\left(-2\right)^3=-2^3=-8$

f) $-2^3=-8$

g) $23^0=1$

h) $\left(-81\right)^0=1$

i) $4^{-3}=\frac{1}{4^3}=\frac{1}{64}$

j) $2^{-5}=\frac{1}{2^5}=\frac{1}{32}$

k) $0^{20}=0$

l) $3^{-3}=\frac{1}{3^3}=\frac{1}{27}$

m) $\left(\frac{1}{3}\right)^3=\frac{1^3}{3^3}=\frac{1}{3^3}=\frac{1}{27}$

n) $\left(\frac{2}{5}\right)^2=\frac{2^2}{5^2}=\frac{4}{5^2}=\frac{4}{25}=0,16$

o) $\left(-2\right)^4=2^4=16$

02.

a) $5^2\cdot \:5^7\cdot \:5^4=5^{2+7+4}=5^{13}$

b) $\frac{3^{12}}{3^{17}}=3^{12-17}=3^{-5}=\frac{1}{3^5}=\frac{1}{243}$

c) $\left(2^2\right)^3=2^{2\cdot \:3}=2^6=64$

d) $2^{2^3}=2^8=256$

e) $\left(2^3\right)^2=2^{3\cdot \:2}=2^6=64$

f) $2^{3^2}=2^9=512$

g) $\frac{3^5\cdot \:3^7}{2\cdot \:2^{11}}=\frac{3^{12}}{2^{11}\cdot \:2}=\frac{3^{12}}{2^{12}}=\frac{531441}{2^{12}}=\frac{531441}{4096}$

03. $\frac{2^{22}}{2}=\frac{2^{22}}{2^1}=2^{22-1}=2^{21}=2097152$

04. $\left(2^4\right)^{3^2}=2^{4\cdot \:3^2}=2^{4\cdot \:9}=d)\:\double2^{36}$

05. $\left(\frac{2^9}{\left(2^2\cdot \:2\right)^3}\right)^{-3}=\frac{1}{\left(\frac{2^9}{\left(2^2\cdot \:2\right)^3}\right)^3}=\frac{1}{\left(\frac{512}{\left(4\cdot \:2\right)^3}\right)^3}=\frac{1}{\left(\frac{512}{512}\right)^3}=\frac{1}{\left(1)\right^3}=\frac{1}{1}=1$