Question

determine o oitavo termo na pg [1/64, 1/32, 1/16, 1/8, ....

Answer 1

Use a fórmula do termo geral:

$a_1= \frac{1}{64} \\ \\ a_2= \frac{1}{32} \\ \\ q= \dfrac{ \frac{1}{32} }{ \frac{1}{64} } \rightarrow q=2 \\ \\ a_8=\,? \\ \\ \\ a_n=a_1\cdot q^{n-1} \\ \\ a_8= \frac{1}{64} \cdot2^{8-1} \\ \\ a_8= \frac{1}{64} \cdot2^7 \\ \\ a_8= \frac{1}{64} \cdot128 \\ \\ \boxed{a_8=2}$