Question

x=(aij) 4×2 de modo que aij=2i2-j

Answer 1

$\left[\begin{array}{ccc}X11&X12&\\X21&X22&\\X31&X32&&X41&X42&\end{array}\right] X11=2.1.2-1=3 X12=2.1.2-2=2 X21=2.2.2-1=7 X22=2.2.2-2=6 X31=2.3.2-1=11 X32=2.3.2-2=10 X41=2.4.2-1=15 X42=2.4.2-2=14 Com isso,a formacao da matriz ficara assim: \left[\begin{array}{ccc}3&2&\\7&6&\\11&10&&15&14\end{array}\right]$