Question

CEVO – 2021) Qual a quantidade de moléculas presentes em 36g de glicose (C6H12O6)? [Massa Molar (C6H12O6) = 180g/mol] *

1,2 x 10²³

2,4 x 10²³

2,0 x 10²³

5,4 x 10²³

32 x 10²³


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Answer 1

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$\boxed{\begin{array}{l}\underline{\rm Observe~com~atenc_{\!\!,}\tilde ao~os~dados~que~podemos}\\\underline{\rm extrair~do~composto~C_6H_{12}O_6:}\\\sf 1~mol~de~mol\acute eculas\\\sf 6\cdot10^{23}~mol\acute eculas\\\sf24~mols~de~\acute atomos\\\sf 24\cdot6\cdot10^{23}~\acute atomos\\\sf 180~g.\\\underline{\sf qual~destas~informac_{\!\!,}\tilde oes~nos~ajuda~a~resolver}\\\underline{\sf o~problema ?}\\\sf a~resposta~\acute e~a~2^a~e~5^a~informac_{\!\!,}\tilde oes.\end{array}}$

$\large\boxed{\begin{array}{l}\sf Assim~podemos~escrever:\\\sf 6\cdot10^{23}~mol\acute eculas\longrightarrow 180~g\\\sf x~mol\acute eculas\longrightarrow 36\\\sf 180\cdot x=6\cdot10^{23}\cdot36\\\sf x=\dfrac{216\cdot10^{23}}{180}\\\sf x=1,2\cdot10^{23}~mo\ell \acute eculas\end{array}}$