Question

como resolver essa equacao (x+5)x(x+5) prf me ajudem

Answer 1

(x+5).(x+5)
x²+5x+5x+25
x²+10x+25=0
∆=b²-4ac
∆=10²-4.1.25
∆=100-100
∆=0
x=-b±√∆/2a
x=-10-0/2.1
x=-10/2
x=-5
S={-5}