Question

gente me ajuda x^-18x+45=0

Answer 1

Vamos usar Bhaskara

Δ = b²-4ac = (-18)²-4*1*45 = 324-180=144

$x_1= \frac{-b +\sqrt{delta} }{2a} = \frac{-(-18)+ \sqrt{144} }{2} = \frac{18+12}{2} =15 \\ x_2= \frac{-b -\sqrt{delta} }{2a} = \frac{-(-18)- \sqrt{144} }{2} = \frac{18-12}{2} =3 \\ x=(3,15)$