Question

Resolva as operações de fatoriais:
Exemplos:
Adição: 4! + 3! = (4 . 3 . 2 . 1) + (3 . 2 . 1) = 24 + 6 = 30
Subtração: 6! – 4! = (6 . 5 . 4 . 3 . 2 . 1) – (4 . 3 . 2 . 1) = 720 – 24 = 696
Multiplicação: 2! . 5! = 2 . 1 . (5. 4 . 3 . 2 . 1) = 2 . 120 = 240
a) 5! + 3!=
b) 4! + 2! =
c) 6! + 4! =
d) 5! - 3! =
e) 4! - 2! =
f) 7! - 4! =
g) 5! . 3! =
h) 4! · 2! =
i) 6! · 4! =

Answer 1

a) 5! + 3!= ( 5 . 4 . 3 . 2 . 1 ) + ( 3 . 2 . 1 ) = 120 + 6 = 126

b) 4! + 2! = ( 4 . 3 . 2 . 1 ) + ( 2 . 1 ) = 24 + 2 = 26

c) 6! + 4! = ( 6 . 5 . 4 . 3 . 2 . 1 ) + ( 4 . 3 . 2 . 1 ) = 600 + 24 = 624

d) 5! - 3! = ( 5 . 4 . 3 . 2 . 1 ) - ( 3 . 2 . 1 ) = 120 - 6 = 114

e) 4! - 2! = ( 4 . 3 . 2 . 1 ) - ( 2 . 1 ) = 24 - 2 = 22

f) 7! - 4! = ( 7 . 6 . 5 . 4 . 3 . 2 . 1 ) - ( 4 . 3 . 2 . 1 ) = 5040 - 24 = 5016

g) 5! . 3! = ( 5 . 4 . 3 . 2 . 1 ) . ( 3 . 2 . 1 ) = 120 . 6 = 720

h) 4! · 2! = ( 4 . 3 . 2 . 1 ) . ( 2 . 1 ) = 24 . 2 = 48

i) 6! · 4! = ( 6 . 5 . 4 . 3 . 2 . 1 ) . ( 4 . 3 . 2 . 1 ) = 1440 . 24 = 34560

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