Question

$25 {x - 20x + 4} = 0$
me ajudem pfvrrrr
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Answer 1

Resposta:

Olá! :)

$25x^2-20x+4=0$

$delta= b^2-4.a.c\\delta= (-20)^2- 4.(25). (4)\\delta= 400-400\\delta= 0$

$x'= -b+\sqrt{delta}/ 2.a\\x'= 20+ 0/ 2.25\\x'= 20/50\\x'= 2/5\\x'= 0,4\\\\x"= -b-\sqrt{0}/ 2.a\\x"= 20-0/ 2.25\\x"= 20/50\\x"= 2/5\\x"= 0,4$

x'= x"

S={$\frac{2}{5}$ (0,4)}

Resposta: x= 2/5 ou 0,4.

Espero ter ajudado! <3