Question

Qual o valor de:

x²+2xy+y²
¯¯¯¯¯¯¯¯¯¯¯¯¯
x²+xy-3x-3x


Sendo q x= - 2
e y= 4

??? :(​

Answer 1

Resposta:

0,5

Explicação passo-a-passo:

$\frac{x^2+2xy+y^2}{x^2+xy-3x-3x}=\\\\\frac{(-2)^2+2(-2)(4)+(4)^2}{(-2)^2+(-2)(4)-3(-2)-3(-2)}=\\\\\frac{4+2(-2)(4)+16}{4+(-2)(4)-3(-2)-3(-2)}=\\\\\frac{4-4(4)+16}{4-8+6+6}=\\\\\frac{4-16+16}{4-8+6+6}=\\\\\frac{4}{-4+6+6}=\\\\\frac{4}{2+6}=\\\\\frac{4}{8}=\\\\\frac{1}{2}=0,5$