Question

1)Resolva as equações exponenciais:

Answer 1

Resposta:

Olá!

Explicação passo-a-passo:

$3^x=\sqrt{3}$

$3^x=3^{\frac{1}{2}}$

$x=\frac{1}{2}$

$4^x=\sqrt[3]{32}$

$4^x=\sqrt[3]{2.2.2.2.2}$

$(2^2)^x=\sqrt[3]{2^5}$

$2^{2x}=2^\frac{5}{3}$

$2x=\frac{5}{3}$

$x=\frac{5}{3} .\frac{1}{2}$

$x=\frac{5}{6}$

Bons Estudos!

Answer 2

Resposta:

=

3

3^x=3^{\frac{1}{2}}3

x

=3

2

1

x=\frac{1}{2}x=

2

1

4^x=\sqrt[3]{32}4

x

=

3

32

4^x=\sqrt[3]{2.2.2.2.2}4

x

=

3

2.2.2.2.2

(2^2)^x=\sqrt[3]{2^5}(2

2

)

x

=

3

2

5

2^{2x}=2^\frac{5}{3}2

2x

=2

3

5

2x=\frac{5}{3}2x=

3

5

x=\frac{5}{3} .\frac{1}{2}x=

3

5

.

2

1

x=\frac{5}{6}x=

6

5

Bons Estudos