Question

2. Um termômetro que marca 382 K estará marcando na escala Celsius, o valor de: *

Answer 1

$\boxed{\dfrac{T_C}{5}=\dfrac{T_F-32}{9}=\dfrac{T_K-273}{5}}$

$\Longrightarrow \dfrac{T_C}{5}=\dfrac{T_K-273}{5}\ \therefore\ \boxed{T_C=T_K-273}$

$T_K=382\ K\Longrightarrow T_C=382-273\ \therefore\ \boxed{T_C=109^{\circ}C}$