Question

o 10° termo da sequencia 64,32,16 vale?​

Answer 1

$\{a_1,a_2,a_3,\cdots\}\equiv\{64,32,16,\cdots\}$

$\boxed{a_n=a_kq^{n-k}}\Longrightarrow a_2=a_1q\Longrightarrow q=\dfrac{a_2}{a_1}=\dfrac{32}{64}\ \therefore\ \boxed{q=\dfrac{1}{2}}$

$a_{10}=a_1q^9\Longrightarrow a_{10}=64\bigg(\dfrac{1}{2}\bigg)^9=\dfrac{2^6}{2^9}=\dfrac{1}{2^3}\ \therefore\ \boxed{a_{10}=\dfrac{1}{8}}$