Question

Resolva as seguintes logarítmicas.


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Answer 1

a) log2 128
log2 2^7 = x
2^x = 2^7
x = 7

b) log√3 9
log√3 3² = x
3^(1/2)^x  = 3²
3^(x/2) = 3²
x/2 = 2
x = 4

c) log1/9 3√3
log1/3²  3√3 = x
log3-² √27 =x
log3-² √3³ = x
log3-² 3^3/2 = x
3^(-2)^x = 3^(3/2)
-2x = 3/2
2x = -3/2
x = (-3/2)/2
x = -3/4

d) log10 10000
log10 10^4 = x
10^x = 10^4
x = 4

Espero ter ajudado.