Question

Dada a função afim f(x) = -2x 3, determine: f(1); f(0); f(1/3);f(-1/2) (x)=0,75

Answer 1

f(x) = -2x + 3
f(1) = -2(1) + 3==> - 2 + 3 ==> 1

f(0) = -2(0) + 3==> 0 + 3 ==> 3

f(1/3) = -2(1/3) + 3==> - 2/3 + 3 ==> ( -2+9)/3 ==7/3

f(-1/2) = -2(-1/2) + 3==> 1 + 3 ==> 4

 -2x + 3 = 0,75

 2x = 3 - 0,75

2x = 2,25

x = 2,25/2 ou 225/100