• Matéria: Matemática
  • Autor: sarasudalaife12
  • Perguntado 9 anos atrás

Como fazer a conta: log 0,2 na base √25 ?

Respostas

respondido por: Verkylen
0
\log_{\sqrt{25}}0{,}2\Longrightarrow\log_{5}0{,}2\\\\\\\log_50{,}2=x\Longleftrightarrow0{,}2=5^x\\\\\\\dfrac{2}{10}=5^x\\\\\\\dfrac{1}{5}=5^x\\\\\\5^{-1}=5^x\\\\\\\therefore\ x=-1\\\\\\\\\boxed{\log_{\sqrt25}0{,}2=-1}
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