• Matéria: Matemática
  • Autor: fs3760709
  • Perguntado 4 anos atrás

Efetue as operações a baixo

A)9/3.4/2
B)3/6.2/7
C)4/5.6/2
D)3/6.12/8



Ajuda aí glr pfv

Respostas

respondido por: Anônimo
4

A)

 \frac{9}{3}  \times  \frac{4}{2}  =  \frac{36}{6}  = ‌\boxed{{\sf\color{orange}{6} {}}} \\

B)

 \frac{3}{6}  \times  \frac{2}{7}  =  \frac{6}{42}  =  ‌\boxed{{\sf\color{orange}{ \frac{1}{7} } {}}} \\

C)

 \frac{4}{5}  \times  \frac{6}{2}  = ‌\boxed{{\sf\color{orange}{ \frac{24}{10} } {}}}  \\

D)

 \frac{3}{6}  \times  \frac{12}{8}  =  \frac{36}{48}  =  \frac{18}{24}  =  \frac{9}{12} =  ‌\boxed{{\sf\color{orange}{ \frac{3}{4} } {}}} \\

espero ter ajudado!

respondido por: CyberKirito
1

Caso esteja pelo app, e tenha problemas para visualizar esta resposta, experimente abrir pelo navegador https://brainly.com.br/tarefa/41572858

                                                   

\boxed{\begin{array}{l}\tt a)~\sf\dfrac{\backslash\!\!\!9^3}{\backslash\!\!\!3_1}\cdot\dfrac{\backslash\!\!\!4^2}{\backslash\!\!\!2_1}=3\cdot2=6\\\tt b)~\sf\dfrac{\diagdown\!\!\!3^1}{\diagdown\!\!\!6_2}\cdot\dfrac{2}{7}=\dfrac{1}{\backslash\!\!\!2}\cdot\dfrac{\backslash\!\!\!2}{7}=\dfrac{1}{7}\\\tt c)~\sf\dfrac{4}{5}\cdot\dfrac{\backslash\!\!\!6^3}{\backslash\!\!\!2_1}=\dfrac{4}{5}\cdot3=\dfrac{12}{5}\end{array}}

\large\boxed{\begin{array}{l}\tt d)~\sf\dfrac{3}{6}\cdot\dfrac{12}{8}=\dfrac{36\div12}{48\div12}=\dfrac{3}{4}\end{array}}

Perguntas similares